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<blockquote data-quote="invitro" data-source="post: 150950" data-attributes="member: 446">Thanks for the feedback.&nbsp; This formula would make the difference between #1 and #10 equal to the difference between #10 and #100, though.&nbsp; I require #100 to be worth one point, so #10 would be worth about 50 points, and that's even lower than what happens in the exp formula, where #10 is worth 66 points.&nbsp; (To fix f(1) = 100 and f(100) = 1, I get a formula of f(x) = 100 * (1 - log(x)/log(104.76)), which gives f(10) = 50.5.)I am unsure that I did that right.I suppose I should try to be more specific about the values of the desired function f(x).&nbsp; I require f(1) = 100 and f(100) = 1.&nbsp; I think we want f(50) to be worth more than the current exp formula gives, which is 10.2, so maybe f(50) = 20 (I'm guessing).&nbsp; And I want ranks #101-500 to be worth more also, so maybe f(250) = 0.1, and f(500) = 0.01.Here is a table of various functions.&nbsp; They are:linear: PTS = 101 - RANKexp: PTS = 100 * exp(-0.0465 * (RANK - 1))log: PTS = 100 * (1 - log(RANK)/log(104.76))power: PTS = 100 * ( (1 - (RANK-1)/499) ^ 20.825)RANK |&nbsp;&nbsp; linear&nbsp; &nbsp; &nbsp; exp&nbsp; &nbsp; &nbsp; log&nbsp; &nbsp; power&nbsp; desired |&nbsp;&nbsp; 1 |&nbsp; 100.000&nbsp; 100.000&nbsp; 100.000&nbsp; 100.000&nbsp; 100.000 |&nbsp;&nbsp; 2 |&nbsp;&nbsp; 99.000&nbsp;&nbsp; 95.456&nbsp;&nbsp; 85.099&nbsp;&nbsp; 95.909&nbsp; &nbsp; &nbsp; &nbsp; ? |&nbsp;&nbsp; 4 |&nbsp;&nbsp; 97.000&nbsp;&nbsp; 86.979&nbsp;&nbsp; 70.198&nbsp;&nbsp; 88.199&nbsp; &nbsp; &nbsp; &nbsp; ? |&nbsp;&nbsp; 8 |&nbsp;&nbsp; 93.000&nbsp;&nbsp; 72.217&nbsp;&nbsp; 55.297&nbsp;&nbsp; 74.513&nbsp; &nbsp; &nbsp; &nbsp; ? |&nbsp; 10 |&nbsp;&nbsp; 91.000&nbsp;&nbsp; 65.803&nbsp;&nbsp; 50.500&nbsp;&nbsp; 68.453&nbsp;&nbsp; 70.000?? |&nbsp; 20 |&nbsp;&nbsp; 81.000&nbsp;&nbsp; 41.333&nbsp;&nbsp; 35.599&nbsp;&nbsp; 44.556&nbsp; &nbsp; &nbsp; &nbsp; ? |&nbsp; 50 |&nbsp;&nbsp; 51.000&nbsp;&nbsp; 10.244&nbsp;&nbsp; 15.901&nbsp;&nbsp; 11.620&nbsp; &nbsp; &nbsp; &nbsp; ? |&nbsp;100 |&nbsp; &nbsp; 1.000&nbsp; &nbsp; 1.002&nbsp; &nbsp; 1.000&nbsp; &nbsp; 1.000&nbsp; &nbsp; 1.000 |&nbsp;250 | -149.000&nbsp; &nbsp; 0.001&nbsp; -18.698&nbsp; &nbsp; 0.000&nbsp; &nbsp; 0.100 |&nbsp;500 | -399.000&nbsp; &nbsp; 0.000&nbsp; -33.599&nbsp; &nbsp; 0.000&nbsp; &nbsp; 0.010 |(I am messing around with the power function.)Well, I am not sure what to think.&nbsp; Except that it seems that it's required to decide how many points #10 and #50 should be worth.</blockquote>

[QUOTE="invitro, post: 150950, member: 446"] Thanks for the feedback. This formula would make the difference between #1 and #10 equal to the difference between #10 and #100, though. I require #100 to be worth one point, so #10 would be worth about 50 points, and that's even lower than what happens in the exp formula, where #10 is worth 66 points. (To fix f(1) = 100 and f(100) = 1, I get a formula of f(x) = 100 * (1 - log(x)/log(104.76)), which gives f(10) = 50.5.) I am unsure that I did that right. I suppose I should try to be more specific about the values of the desired function f(x). I require f(1) = 100 and f(100) = 1. I think we want f(50) to be worth more than the current exp formula gives, which is 10.2, so maybe f(50) = 20 (I'm guessing). And I want ranks #101-500 to be worth more also, so maybe f(250) = 0.1, and f(500) = 0.01. Here is a table of various functions. They are: linear: PTS = 101 - RANK exp: PTS = 100 * exp(-0.0465 * (RANK - 1)) log: PTS = 100 * (1 - log(RANK)/log(104.76)) power: PTS = 100 * ( (1 - (RANK-1)/499) ^ 20.825) RANK | linear exp log power desired | 1 | 100.000 100.000 100.000 100.000 100.000 | 2 | 99.000 95.456 85.099 95.909 ? | 4 | 97.000 86.979 70.198 88.199 ? | 8 | 93.000 72.217 55.297 74.513 ? | 10 | 91.000 65.803 50.500 68.453 70.000?? | 20 | 81.000 41.333 35.599 44.556 ? | 50 | 51.000 10.244 15.901 11.620 ? | 100 | 1.000 1.002 1.000 1.000 1.000 | 250 | -149.000 0.001 -18.698 0.000 0.100 | 500 | -399.000 0.000 -33.599 0.000 0.010 | (I am messing around with the power function.) Well, I am not sure what to think. Except that it seems that it's required to decide how many points #10 and #50 should be worth. [/QUOTE]

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