Search titles only
By:
Home
Forums
New posts
Search forums
Articles
New articles
New comments
Search articles
Pinball DB
Pinball Tables
Pinball Games
What's new
New posts
New articles
New profile posts
New article comments
Latest activity
Log in
Register
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Navigation
Install the app
Install
More options
Contact us
Close Menu
Welcome Back to Digital Pinball Fans -
please read this first
For latest updates, follow Digital Pinball Fans on
Facebook
and
Twitter
Home
Forums
Farsight Studios
The Pinball Arcade / Farsight Studios
(An attempt at) The top 40 TPA players from leaderboard scores
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="invitro" data-source="post: 150950" data-attributes="member: 446"><p>Thanks for the feedback. This formula would make the difference between #1 and #10 equal to the difference between #10 and #100, though. I require #100 to be worth one point, so #10 would be worth about 50 points, and that's even lower than what happens in the exp formula, where #10 is worth 66 points. (To fix f(1) = 100 and f(100) = 1, I get a formula of f(x) = 100 * (1 - log(x)/log(104.76)), which gives f(10) = 50.5.)</p><p></p><p>I am unsure that I did that right.</p><p></p><p>I suppose I should try to be more specific about the values of the desired function f(x). I require f(1) = 100 and f(100) = 1. I think we want f(50) to be worth more than the current exp formula gives, which is 10.2, so maybe f(50) = 20 (I'm guessing). And I want ranks #101-500 to be worth more also, so maybe f(250) = 0.1, and f(500) = 0.01.</p><p></p><p>Here is a table of various functions. They are:</p><p>linear: PTS = 101 - RANK</p><p>exp: PTS = 100 * exp(-0.0465 * (RANK - 1))</p><p>log: PTS = 100 * (1 - log(RANK)/log(104.76))</p><p>power: PTS = 100 * ( (1 - (RANK-1)/499) ^ 20.825)</p><p></p><p>RANK | linear exp log power desired |</p><p> 1 | 100.000 100.000 100.000 100.000 100.000 |</p><p> 2 | 99.000 95.456 85.099 95.909 ? |</p><p> 4 | 97.000 86.979 70.198 88.199 ? |</p><p> 8 | 93.000 72.217 55.297 74.513 ? |</p><p> 10 | 91.000 65.803 50.500 68.453 70.000?? |</p><p> 20 | 81.000 41.333 35.599 44.556 ? |</p><p> 50 | 51.000 10.244 15.901 11.620 ? |</p><p> 100 | 1.000 1.002 1.000 1.000 1.000 |</p><p> 250 | -149.000 0.001 -18.698 0.000 0.100 |</p><p> 500 | -399.000 0.000 -33.599 0.000 0.010 |</p><p></p><p>(I am messing around with the power function.)</p><p></p><p>Well, I am not sure what to think. Except that it seems that it's required to decide how many points #10 and #50 should be worth.</p></blockquote><p></p>
[QUOTE="invitro, post: 150950, member: 446"] Thanks for the feedback. This formula would make the difference between #1 and #10 equal to the difference between #10 and #100, though. I require #100 to be worth one point, so #10 would be worth about 50 points, and that's even lower than what happens in the exp formula, where #10 is worth 66 points. (To fix f(1) = 100 and f(100) = 1, I get a formula of f(x) = 100 * (1 - log(x)/log(104.76)), which gives f(10) = 50.5.) I am unsure that I did that right. I suppose I should try to be more specific about the values of the desired function f(x). I require f(1) = 100 and f(100) = 1. I think we want f(50) to be worth more than the current exp formula gives, which is 10.2, so maybe f(50) = 20 (I'm guessing). And I want ranks #101-500 to be worth more also, so maybe f(250) = 0.1, and f(500) = 0.01. Here is a table of various functions. They are: linear: PTS = 101 - RANK exp: PTS = 100 * exp(-0.0465 * (RANK - 1)) log: PTS = 100 * (1 - log(RANK)/log(104.76)) power: PTS = 100 * ( (1 - (RANK-1)/499) ^ 20.825) RANK | linear exp log power desired | 1 | 100.000 100.000 100.000 100.000 100.000 | 2 | 99.000 95.456 85.099 95.909 ? | 4 | 97.000 86.979 70.198 88.199 ? | 8 | 93.000 72.217 55.297 74.513 ? | 10 | 91.000 65.803 50.500 68.453 70.000?? | 20 | 81.000 41.333 35.599 44.556 ? | 50 | 51.000 10.244 15.901 11.620 ? | 100 | 1.000 1.002 1.000 1.000 1.000 | 250 | -149.000 0.001 -18.698 0.000 0.100 | 500 | -399.000 0.000 -33.599 0.000 0.010 | (I am messing around with the power function.) Well, I am not sure what to think. Except that it seems that it's required to decide how many points #10 and #50 should be worth. [/QUOTE]
Verification
Post reply
Members online
No members online now.
Latest posts
D
Anyone still playing?
Latest: Dan
Mar 3, 2025
The Pinball Arcade / Farsight Studios
Home
Forums
Farsight Studios
The Pinball Arcade / Farsight Studios
(An attempt at) The top 40 TPA players from leaderboard scores
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
Accept
Learn more…
Top